If the hydraulic radius for full flow condition is calculated as D/4, what does this refer to?

Disable ads (and more) with a premium pass for a one time $4.99 payment

Prepare thoroughly for the PE Civil Water Resources and Environmental exam with engaging quizzes and detailed explanations of key concepts. Enhance your study efforts with relevant questions to boost confidence and proficiency.

The hydraulic radius is defined as the ratio of the flow area to the wetted perimeter in open channel flow. In the case of a circular pipe flowing full, the hydraulic radius (R) can be calculated using the formula R = A/P, where A is the flow area and P is the wetted perimeter.

For a fully flowing circular pipe, the flow area (A) can be determined as the area of the circle (A = πD²/4) and the wetted perimeter (P) is equal to the diameter (P = D). Therefore, the hydraulic radius can be calculated as:

[ R = \frac{A}{P} = \frac{\frac{\pi D^2}{4}}{D} = \frac{\pi D}{4} ]

However, when considering only the relationship of D/4, it signifies a specific ratio derived from the full flow condition, indicating that the hydraulic radius in this instance is a quarter of the diameter of the pipe (D).

This unique relationship is particularly important in hydraulic design and analysis as it helps characterize flow behavior under full flow conditions. It is essentially noting that when we consider D divided by 4, we are explicitly referring to one-fourth of the diameter

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy